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If the dipole moment of HCl is 1.08 D an...

If the dipole moment of HCl is 1.08 D and the bond distance is `1.27Å`, the partial charge on hydrogen and chlorine , respectively are

A

`+1.0 and -1.0`

B

`+.85 and -.85`

C

`+0.356 and -0.356`

D

`+0.177 and -0.177`

Text Solution

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The correct Answer is:
To find the partial charges on hydrogen and chlorine in HCl, we can use the dipole moment formula and the given values. Here’s a step-by-step solution: ### Step 1: Understand the Dipole Moment The dipole moment (μ) is given by the formula: \[ \mu = Q \times D \] where: - \( \mu \) is the dipole moment, - \( Q \) is the partial charge, - \( D \) is the bond distance. ### Step 2: Convert Units We need to convert the bond distance from angstroms to meters: \[ 1 \text{ Å} = 10^{-10} \text{ m} \] Thus, \[ D = 1.27 \text{ Å} = 1.27 \times 10^{-10} \text{ m} \] ### Step 3: Convert Dipole Moment to SI Units The dipole moment is given as 1.08 D. We need to convert this to coulomb-meters: Using the conversion: \[ 1 \text{ D} = 3.34 \times 10^{-29} \text{ C m} \] So, \[ \mu = 1.08 \text{ D} = 1.08 \times 3.34 \times 10^{-29} \text{ C m} \] Calculating this gives: \[ \mu = 3.6072 \times 10^{-29} \text{ C m} \] ### Step 4: Rearrange the Dipole Moment Formula Now, we can rearrange the dipole moment formula to solve for the partial charge \( Q \): \[ Q = \frac{\mu}{D} \] ### Step 5: Substitute the Values Substituting the values we have: \[ Q = \frac{3.6072 \times 10^{-29} \text{ C m}}{1.27 \times 10^{-10} \text{ m}} \] ### Step 6: Calculate the Partial Charge Calculating this gives: \[ Q = 2.838 \times 10^{-19} \text{ C} \] ### Step 7: Find the Fractional Charge To find the fractional charge, we can compare it to the charge of an electron, which is: \[ e = 1.6 \times 10^{-19} \text{ C} \] Thus, the fractional charge is: \[ \text{Fractional Charge} = \frac{Q}{e} = \frac{2.838 \times 10^{-19}}{1.6 \times 10^{-19}} \approx 0.177 \] ### Final Result The partial charges on hydrogen and chlorine are: - Partial charge on Hydrogen (H): \( +0.177e \) - Partial charge on Chlorine (Cl): \( -0.177e \)
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