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Mahesh (who is colourblind) and soni (wh...

Mahesh (who is colourblind) and soni (who is not colourblind have q daughter Alia. Rish ( who is not colourblind) and Neetu (who is a carrier ) have a son Ranbeer . Alia and Ranbeer get married . What is the probability that their daughter will be colourblind ?

A

`0%`

B

`25%`

C

`50%`

D

`75%`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we need to analyze the genetic information provided about the individuals involved and their offspring. ### Step 1: Understand the Genetics of Colorblindness Colorblindness is a sex-linked recessive trait, which means it is carried on the X chromosome. Males have one X and one Y chromosome (XY), while females have two X chromosomes (XX). A male will be colorblind if he has the recessive allele (XcY), while a female will be colorblind only if she has two copies of the recessive allele (XcXc). If she has one normal allele (X) and one recessive allele (Xc), she will be a carrier (XcX). ### Step 2: Determine the Genotypes of Mahesh and Soni - Mahesh is colorblind, so his genotype is XcY. - Soni is not colorblind, and since she has a daughter with Mahesh, she must have at least one normal allele. Therefore, her genotype is XX (homozygous normal) or XcX (heterozygous carrier). However, since Alia (their daughter) is not colorblind, we can conclude that Soni is XX. ### Step 3: Determine the Genotype of Alia Since Mahesh is XcY and Soni is XX, Alia must inherit one X chromosome from each parent: - From Mahesh: Xc - From Soni: X Thus, Alia's genotype is XcX (she is a carrier but not colorblind). ### Step 4: Determine the Genotypes of Rish and Neetu - Rish is not colorblind, so his genotype is XY (normal). - Neetu is a carrier, so her genotype is XcX. ### Step 5: Determine the Genotypes of Ranbeer When Rish and Neetu have a son (Ranbeer), the possible combinations of their alleles are: - From Rish (XY): X or Y - From Neetu (XcX): Xc or X The possible genotypes for Ranbeer are: 1. XY (not colorblind) 2. XcY (colorblind) Thus, there is a 50% chance that Ranbeer is colorblind and a 50% chance that he is not. ### Step 6: Determine the Possible Genotypes of Alia and Ranbeer’s Daughter Now, Alia (XcX) and Ranbeer (XY or XcY) can have the following combinations for their daughter: 1. If Ranbeer is XY (not colorblind): - Possible combinations: XcX (carrier, not colorblind) or XX (not colorblind) 2. If Ranbeer is XcY (colorblind): - Possible combinations: XcX (carrier, not colorblind) or XcXc (colorblind) ### Step 7: Calculate the Probability of Their Daughter Being Colorblind - If Ranbeer is XY (50% chance), the daughter will not be colorblind. - If Ranbeer is XcY (50% chance), the daughter has a 50% chance of being colorblind. Thus, the overall probability that their daughter will be colorblind is: - Probability = (0.5 * 0) + (0.5 * 0.5) = 0 + 0.25 = 0.25 or 25%. ### Final Answer The probability that Alia and Ranbeer’s daughter will be colorblind is **25%**.
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