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The ratio of F2 generation of a dihybrid...

The ratio of F2 generation of a dihybrid cross having pure , monohybrids , dihybrids plants is

A

`1:2:1`

B

`1:2:4`

C

`1:4:8`

D

`1:1:2`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding the ratio of the F2 generation of a dihybrid cross involving pure, monohybrid, and dihybrid plants, we can follow these steps: ### Step 1: Understand the Dihybrid Cross A dihybrid cross involves two traits, each represented by two alleles. For example, let's consider two traits: A (dominant) and a (recessive) for the first trait, and B (dominant) and b (recessive) for the second trait. ### Step 2: Set Up the Parental Generation Assume we have two pure parental lines: - Parent 1: AABB (homozygous dominant for both traits) - Parent 2: aabb (homozygous recessive for both traits) ### Step 3: Determine the F1 Generation When these two parents are crossed (AABB x aabb), all offspring in the F1 generation will be heterozygous for both traits: - F1 Generation: AaBb ### Step 4: Perform the Dihybrid Cross for F2 Generation Now, we will cross the F1 generation with itself (AaBb x AaBb). We can use a Punnett square to determine the offspring ratios. ### Step 5: Create a Punnett Square The gametes from each parent (AaBb) will be: - AB, Ab, aB, ab Setting up the Punnett square, we get: | | AB | Ab | aB | ab | |------|-----|-----|-----|-----| | **AB** | AABB | AABb | AaBB | AaBb | | **Ab** | AABb | AAbb | AaBb | Aabb | | **aB** | AaBB | AaBb | aaBB | aaBb | | **ab** | AaBb | Aabb | aaBb | aabb | ### Step 6: Count the Ratios From the Punnett square, we can count the phenotypes: - 1 AABB (homozygous dominant for both traits) - 2 AABb (homozygous dominant for the first trait, heterozygous for the second) - 2 AaBB (heterozygous for the first trait, homozygous dominant for the second) - 4 AaBb (heterozygous for both traits) - 1 AAbb (homozygous recessive for the first trait, heterozygous for the second) - 2 Aabb (heterozygous for the first trait, homozygous recessive for the second) - 1 aabb (homozygous recessive for both traits) Thus, the ratio of the F2 generation is: - 1 : 2 : 2 : 4 : 1 : 2 : 1 ### Step 7: Simplify the Ratio The simplified ratio of phenotypes for a dihybrid cross is: - 9:3:3:1 for the dominant and recessive traits. ### Conclusion The correct answer for the ratio of the F2 generation of a dihybrid cross is **9:3:3:1**.
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