Home
Class 12
CHEMISTRY
How much heat is required to change 10 g...

How much heat is required to change 10 g ice at `0^@C` to steam at `100^@C`? Latent heat of fusion and vapour for `H_2O` are 80 cal/g and 540 cal/g respectively. Specific heat of water is 1 cal/g.

A

7200 cal

B

3600 cal

C

1800 cal

D

900 cal

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Similar Questions

Explore conceptually related problems

How much heat is required to change 10g ice at 0^(@)C to steam at 100^(@)C ? Latent heat of fusion and vaporisation for H_(2)O are 80 cl g^(-1) and 540 cal g^(-1) , respectively. Specific heat of water is 1cal g^(-1) .

How much heat is required to change 10g ice at 10^(@)C to steam at 100^(@)C ? Latent heat of fusion and vaporisation for H_(2)O are 80 cl g^(-1) and 540 cal g^(-1) , respectively. Specific heat of water is 1cal g^(-1) .

How many calories of heat will be required to convert 1 g of ice at 0^(@)C into steam at 100^(@)C

Steam at 100°C is passed into 100 g of ice at 0°C . Finally when 80g ice melts the mass of water present will be [Latent heat of fusion and vaporazisation are 80 cal g^(-1) and 540 cal g^(-1) respectively, specific heat of water = 1 cal g^(-1) °C^(-1) ]

The amount of heat required to raise the temperature of 75 kg of ice at 0^oC to water at 10^oC is (latent heat of fusion of ice is 80 cal/g, specific heat of water is 1 cal/ g^oC )

How much heat is required to convert 8.0 g of ice at -15^@C to steam at 100^@C ? (Given, c_(ice) = 0.53 cal//g.^@C, L_f = 80 cal//g and L_v = 539 cal//g, and c_(water) = 1 cal//g.^@C) .

How much heat is required to convert 8.0 g of ice at -15^@ to steam at 100^@ ? (Given, c_(ice) = 0.53 cal//g-^@C, L_f = 80 cal//g and L_v = 539 cal//g, and c_(water) = 1 cal//g-^@C) .

1 kg of ice at 0^(@)C is mixed with 1.5 kg of water at 45^(@)C [latent heat of fusion = 80 cal//gl. Then

What is the amount of heat required (in calories) to convert 10 g of ice at -10^(@)C into steam at 100^(@)C ? Given that latent heat of vaporization of water is "540 cal g"^(-1) , latent heat of fusion of ice is "80 cal g"^(-1) , the specific heat capacity of water and ice are "1 cal g"^(-1).^(@)C^(-1) and "0.5 cal g"^(-1).^(@)C^(-1) respectively.

120 g of ice at 0^(@)C is mixed with 100 g of water at 80^(@)C . Latent heat of fusion is 80 cal/g and specific heat of water is 1 cal/ g-.^(@)C . The final temperature of the mixture is