Home
Class 12
PHYSICS
A particle moves with a velocity 5hati-3...

A particle moves with a velocity `5hati-3hatj+6hatk ms^(-1)` under the influence of a constant force F=10hati+10hatj+20hatk N. The instantaneous power applied to the particle is

A

140 W

B

40 W

C

200 W

D

170 W

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Similar Questions

Explore conceptually related problems

A particle moves with a velocity v=(5hati-3hatj + 6hatk) ms^(-1) under the influence of a constant force F =(10hati + 10hatj + 20hath) N , the instantaneous power applied to the particle is.

A particle moves with a velocity v=(5hati-3hatj + 6hatk) ms^(-1) under the influence of a constant force F =(10hati + 10hatj + 20hath) N , the instantaneous power applied to the particle is.

A particle moves with a velocity of (4hati-2hatj+2hatk)ms^(-1) under the influence of a constant force vecF=(10hati+3hatj-2hatk)N . The instantaneous power applied to the particle is

A particle moves with the velocity vecv=(5hati+2hatj-hatk)ms^(-1) under the influence of a constant force, vecF=(2hati+5hatj-10hatk)N. The instantaneous power applied is

A particle moves with the velocity vecv=(5hati+2hatj-hatk)ms^(-1) under the influence of a constant force, vecF=(2hati+5hatj-10hatk)N. The instantaneous power applied is

A body moves from a position vec(r_(1))=(2hati-3hatj-4hatk) m to a position vec(r_(2))=(3hati-4hatj+5hatk)m under the influence of a constant force vecF=(4hati+hatj+6hatk)N . The work done by the force is :

A particle moves from point P(1,2,3) to (2,1,4) under the action of a constant force F=(2hati+hatj+hatk)N . Work done by the force is

A particle moves from point P(1,2,3) to (2,1,4) under the action of a constant force F=(2hati+hatj+hatk)N . Work done by the force is

A particle moves from point (hati+hatj) m to a point (6hati-2hatj) m under the action of force (10hati-2hatj) N. The work done by the force is

A charged particle carrying charge 1 mu C is moving with velocity (2 hati + 3hati + 4hatk) ms^(-1) . If an external magnetic field of (5 hati + 3hatj - 6hatk) xx 10^(-3)T exists in the region where the particle is moving then the force on the particle is vecF xx 10^(-9)N . The vector vecF is :