`Pb(CH_3COO)_2+H_2S to`
Product is:

Complete the following reaction. Also give the colour change : underset("Colourless")(Pb(CH_3COO)_2) + H_2S rarr underset("(__________)")"_______" darr + CH_3COOH

Pb(CH_3COO)_2 gives …….colour with H_2S

CH_(2) = CH_(2) + B_(2) H_(6) underset(H_(2)O_(2))overset(NaOH) to Product is :

Black (A)+H_(2)SO_(4)to (B)"gas"+( C) (B)+(CH_(3)COO)_(2) Pb to (D) black ppt. ( C)+K_(3)[Fe(CN)_(6)] to (E) blue. ( C) also decolourilses acidified KMnO_(4) .Identify (A) to (E)

If Pb[CH_(3)COO]_(2) and Na_(2)S are mixed and dissolved in water and the solution is filtered then the filterate will give test of

Give balanced equation for the conversions A and B . Sulphide Aoverset(Pb(CH_3COO)_2soln.)rarr Black precipitate

On passing CrO_2 Cl_2 in water and then adding (CH_3 COO)_2 Pb, the precipitate formed is

Pb(AcO)_(2)+H_(2)S to PbS darr+2AcOH

Pb(AcO)_(2)+H_(2)S to PbS darr+2AcOH

CH_3CH_2C-=C CH_2CH_3+H_2O overset(HgSO_4)to Product, Product is :