A substance of mass 4.953 g occupies `1.5 cm^(-3)` of volume . The density of the substance (in g `cm^(-3)` ) With correct number of significant figures is

Options

A. (a)3.3
B. (b)`3.300`
C. (c)`3.302`
D. (d)`33.0`

Answer

To find the density of the substance, we can follow these steps:

### Step 1: Identify the given values
- Mass (m) = 4.953 g
- Volume (V) = 1.5 cm³

### Step 2: Use the formula for density
The formula for density (D) is given by:
\[ D = \frac{m}{V} \]
where:
- D is the density,
- m is the mass,
- V is the volume.

### Step 3: Substitute the values into the formula
Substituting the given values into the density formula:
\[ D = \frac{4.953 \, \text{g}}{1.5 \, \text{cm}^3} \]

### Step 4: Perform the calculation
Now, we will perform the division:
\[ D = \frac{4.953}{1.5} \approx 3.302 \, \text{g/cm}^3 \]

### Step 5: Determine the correct number of significant figures
- The mass (4.953 g) has four significant figures.
- The volume (1.5 cm³) has two significant figures.
- The result should be reported with the least number of significant figures, which is two (from the volume).

Thus, we round 3.302 to two significant figures:
\[ D \approx 3.3 \, \text{g/cm}^3 \]

### Final Answer
The density of the substance is:
\[ \boxed{3.3 \, \text{g/cm}^3} \]

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