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Two particles of masses ma and mb and sa...

Two particles of masses `m_a` and `m_b` and same charge are projected in a perpendicular magnetic field . They travel along circular paths of radius `r_(a)` and `r_(b)` such that `r_(a) gt r_(b)` . Then which is true ?

A

`m_a v_a gt m_bv_b`

B

`m_a gt m_b and v_a gt v_b`

C

`m_a = m_b and v_a = v_b`

D

`m_b v_b gt m_a v_a`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, let's analyze the motion of two charged particles in a magnetic field and derive the relationship between their masses and velocities based on the given conditions. ### Step-by-Step Solution: 1. **Understanding the Forces**: When a charged particle moves in a magnetic field, it experiences a magnetic force that acts as the centripetal force required for circular motion. The magnetic force \( F_B \) is given by: \[ F_B = qvB \] where \( q \) is the charge of the particle, \( v \) is its velocity, and \( B \) is the magnetic field strength. 2. **Centripetal Force**: The centripetal force \( F_C \) required to keep a particle moving in a circular path of radius \( R \) is given by: \[ F_C = \frac{mv^2}{R} \] where \( m \) is the mass of the particle and \( v \) is its velocity. 3. **Equating Forces**: For a particle to move in a circular path in a magnetic field, the magnetic force must equal the centripetal force: \[ qvB = \frac{mv^2}{R} \] 4. **Rearranging the Equation**: We can rearrange this equation to express the radius \( R \) in terms of mass \( m \) and velocity \( v \): \[ R = \frac{mv}{qB} \] 5. **Applying to Both Particles**: For particle A with mass \( m_a \) and radius \( r_a \): \[ r_a = \frac{m_a v_a}{qB} \] For particle B with mass \( m_b \) and radius \( r_b \): \[ r_b = \frac{m_b v_b}{qB} \] 6. **Given Condition**: We know that \( r_a > r_b \). Therefore: \[ \frac{m_a v_a}{qB} > \frac{m_b v_b}{qB} \] Since \( q \) and \( B \) are the same for both particles, we can cancel them out: \[ m_a v_a > m_b v_b \] 7. **Conclusion**: This implies that the product of mass and velocity for particle A is greater than that for particle B. Thus, the correct relationship is: \[ m_a v_a > m_b v_b \] ### Final Answer: The correct option is that \( m_a v_a > m_b v_b \).
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