Home
Class 12
PHYSICS
The potential difference that must be ap...

The potential difference that must be applied to stop the fastest photo electrons emitted by a nickel surface, having work function 5.01 eV, when ultraviolet light of 200 nm falls on it, must be –

A

2.4 V

B

`-1.2 V`

C

`-2.4 V`

D

`1.2V`

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Similar Questions

Explore conceptually related problems

The potential difference that must be applied to stop the fastest photoelectrons emitted by a nickel surface , having work function 5.01 eV , when ultraviolet light of 200 nm falls on it , must be

What P.D. must be applied to stop the fastest photo electron emitted by a nickel surface when illuminated by ultraviolet light of wave length 2000^(@)A . The work function of nickel is 5 eV

Will photoelectrons be emitted from a copper surface, of work function 4.4 eV , when illuminated by a visible light?

Find the retarding potential requred to stop the escape of photo electrons from the metal surface of work function 1.07 eV , which is irradiated with light of wavelength 332 mn

Five volt of stopping potential is needed for the photoelectrons emitted out of a surface of work function 2.2 eV by the radiation of wavelength

Calculate the value of retarding potential in volt needed to stop the photoelectron ejected from a metal surface of work function 1.29 eV with light frequency of 5.5 xx 10^(14) sec^(-1) (nearly)

When photon of energy 3.8 eV falls on metallic suface of work function 2.8 eV , then the kinetic energy of emitted electrons are

The stopping potential for the photoelectrons emitted from a metal surface of work function 1.7 eV is 10.4 V. Find the wavelength of the radiation used. Also, identify the energy levels in hydrogen atom, which will emit this wavelength.

If Photon having wavelength 6.2nm was allowed to strike a metal plate having work function 50eV then calculate wavelength associated with emitted electron :

The circumference of the second Bohr orbit of electron in hydrogen atom is 600nm . The potential difference that must be applied between the plates so that the electron have the de Broglie wavelength corresponding in this circumference is