A current of 2.34 A flows in resistance of `11. 111111Omega` The potential difference across the given resistance with due regard for the significant figure is

Options

A. (a)26.000 A
B. (b)26.00 A
C. (c)26.0 V
D. (d)26 V

Answer

To solve the problem step by step, we will use Ohm's Law, which states that the potential difference (V) across a resistor is equal to the current (I) flowing through it multiplied by the resistance (R).

### Step 1: Identify the given values
- Current (I) = 2.34 A
- Resistance (R) = 11.111111 Ω

### Step 2: Apply Ohm's Law
Using the formula:
\[ V = I \times R \]

Substituting the values we have:
\[ V = 2.34 \, \text{A} \times 11.111111 \, \Omega \]

### Step 3: Perform the multiplication
Calculating the product:
\[ V = 2.34 \times 11.111111 \]
\[ V = 25.99999974 \, \text{V} \]

### Step 4: Round off to significant figures
Now, we need to round the result to the correct number of significant figures. The current (2.34 A) has three significant figures, and the resistance (11.111111 Ω) has eight significant figures. Therefore, we should round the potential difference to three significant figures.

The value 25.99999974 rounded to three significant figures is:
\[ V \approx 26.0 \, \text{V} \]

### Final Answer
The potential difference across the given resistance is:
\[ \boxed{26.0 \, \text{V}} \]

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