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In metre bridge experiment, with a stand...

In metre bridge experiment, with a standard resistance in the right gap and a resistance coil dipped in water (in a beaker) in the left gap, the balancing length obtained is '1'. If the temperature of water is increased, the new balancing

A

` lt l`

B

` gt l`

C

` = 0 `

D

`=l`

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The correct Answer is:
To solve the problem regarding the meter bridge experiment, we will follow these steps: ### Step 1: Understand the Initial Setup In the meter bridge experiment, we have a standard resistance \( R \) on one side (right gap) and a resistance coil \( X \) dipped in water on the other side (left gap). The initial balancing length obtained is \( L \). ### Step 2: Apply the Principle of the Meter Bridge According to the principle of the meter bridge (which is based on the Wheatstone bridge principle), the balancing condition is given by: \[ \frac{X}{R} = \frac{L}{100 - L} \] Here, \( L \) is the length of the bridge corresponding to the resistance \( X \), and \( 100 - L \) corresponds to the resistance \( R \). ### Step 3: Consider the Effect of Temperature on Resistance When the temperature of the water increases, the resistance \( X \) of the coil will also increase. This is because the resistance of conductors typically increases with temperature. We denote the new resistance as \( X' \), where \( X' > X \). ### Step 4: Write the New Balancing Condition With the new resistance \( X' \), the new balancing length \( L' \) can be expressed as: \[ \frac{X'}{R} = \frac{L'}{100 - L'} \] Since \( X' > X \), the ratio \( \frac{X'}{R} \) will also be greater than the original ratio \( \frac{X}{R} \). ### Step 5: Analyze the Implications of the Increased Resistance Given that \( \frac{X'}{R} > \frac{X}{R} \), it follows that: \[ \frac{L'}{100 - L'} > \frac{L}{100 - L} \] This indicates that the new balancing length \( L' \) must be greater than the original balancing length \( L \). ### Conclusion Thus, when the temperature of the water is increased, the new balancing length \( L' \) will be greater than the original balancing length \( L \). ### Final Answer The new balancing length \( L' \) will be greater than \( L \).
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