The quantity of a charge that will be transferred by a current flow of 20 A over 1 h 30 min period is

Options

A. `10.8xx10^3C`
B. `10.8xx10^4C`
C. `5.4xx10^3C`
D. `1.8xx10^4C`

Answer

To solve the problem of finding the quantity of charge transferred by a current flow of 20 A over a period of 1 hour and 30 minutes, we can follow these steps:

### Step-by-Step Solution:

1. **Convert the time from hours and minutes to seconds**:
- We have 1 hour and 30 minutes.
- Convert 1 hour to seconds:
\[ 1 \text{ hour} = 3600 \text{ seconds} \]
- Convert 30 minutes to seconds:
\[ 30 \text{ minutes} = 30 \times 60 = 1800 \text{ seconds} \]
- Therefore, the total time in seconds is:
\[ T = 3600 \text{ seconds} + 1800 \text{ seconds} = 5400 \text{ seconds} \]

2. **Use the formula for charge**:
- The formula for charge (Q) is given by:
\[ Q = I \times T \]
- Where \( I \) is the current in amperes and \( T \) is the time in seconds.

3. **Substitute the values into the formula**:
- Given \( I = 20 \text{ A} \) and \( T = 5400 \text{ seconds} \):
\[ Q = 20 \text{ A} \times 5400 \text{ seconds} \]

4. **Calculate the charge**:
- Performing the multiplication:
\[ Q = 20 \times 5400 = 108000 \text{ coulombs} \]
- This can also be expressed in scientific notation as:
\[ Q = 1.08 \times 10^5 \text{ coulombs} \]

5. **Final Answer**:
- The quantity of charge transferred is \( 1.08 \times 10^5 \text{ coulombs} \).