A paramagnetic substance of susceptibility `3 xx10^(-4)` is placed in a magnetic field of `3xx 10^(-4)A m^(-1)`. . Then , the intensity of magnetisation in units of A `m^(-1)` is

Options

A. `9xx10^(-8)`
B. `1xx10^(-4)`
C. `1xx10^(-3)`
D. `9xx10^(-10)`

Answer

To solve the problem, we need to find the intensity of magnetization (I) of a paramagnetic substance given its susceptibility (χ) and the magnetic field intensity (B).

### Step-by-Step Solution:

1. **Identify the given values:**
- Susceptibility (χ) = \(3 \times 10^{-4}\)
- Magnetic field intensity (B) = \(3 \times 10^{-4} \, \text{A/m}\)

2. **Use the formula for intensity of magnetization:**
The relationship between susceptibility, magnetic field intensity, and intensity of magnetization is given by:
\[ I = \chi \cdot B \]
where:
- \(I\) is the intensity of magnetization,
- \(\chi\) is the susceptibility,
- \(B\) is the magnetic field intensity.

3. **Substitute the values into the formula:**
\[ I = (3 \times 10^{-4}) \cdot (3 \times 10^{-4}) \]

4. **Calculate the product:**
\[ I = 9 \times 10^{-8} \, \text{A/m} \]

5. **Final answer:**
The intensity of magnetization is:
\[ I = 9 \times 10^{-8} \, \text{A/m} \]