Home
Class 12
PHYSICS
The displacement x (in metre ) of a part...

The displacement x (in metre ) of a particle in, simple harmonic motion is related to time t ( in second ) as
` x= 0.01 cos (pi t + pi /4)`
the frequency of the motion will be

A

0.5Hz

B

1.0 Hz

C

`pi/2Hz`

D

`piHz`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Similar Questions

Explore conceptually related problems

The displacement x(in metres) of a particle performing simple harmonic motion is related to time t(in seconds) as x=0.05cos(4pit+(pi)/4) .the frequency of the motion will be

The phase (at a time t) of a particle in simple harmonic motion tells

The displacement of a particle in simple harmonic motion in one time period is

The displacement of a particle executing simple harmonic motion is given by y = 4 sin(2t + phi) . The period of oscillation is

The phase difference between displacement and acceleration of particle in a simple harmonic motion is

A particle executes simple harmonic motion and is located at x = a, b and c at times t_(0), 2t_(0) and 3t_(0) respectively. The frequency of the oscillation is :

A particle executes simple harmonic motion and is located at x = a , b at times t_(0),2t_(0) and3t_(0) respectively. The frequency of the oscillation is :

A simple harmonic motion is represented by x(t) = sin^2 omegat - 2 cos^(2) omegat . The angular frequency of oscillation is given by

The total energy of a particle having a displacement x, executing simple harmonic motion is

The velocity v and displacement x of a particle executing simple harmonic motion are related as v (dv)/(dx)= -omega^2 x . At x=0, v=v_0. Find the velocity v when the displacement becomes x.