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A metal surface is illuminated by a ligh...

A metal surface is illuminated by a light of given intensity and frequency to cause photoemission. If the intensity of illumination is reduced to one-fourth of its original value, then the maximum KE of emitted photoelectrons will become.

A

Four times the original value

B

Twice the original value

C

`1//6^(th)` of the original value

D

Unchanged

Text Solution

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The correct Answer is:
D
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