A charge of 8.0 mA in the emitter current brings a charge of 7.9 mA in the collector current. The values of `alpha and beta` are

Options

A. 0.99,90
B. 0.96,79
C. 0.97, 99
D. 0.99 , 79

Answer

To solve the problem, we need to find the values of alpha (α) and beta (β) based on the given changes in emitter current (IE) and collector current (IC).

### Step-by-Step Solution:

1. **Identify the given values:**
- Change in emitter current (ΔIE) = 8.0 mA
- Change in collector current (ΔIC) = 7.9 mA

2. **Calculate alpha (α):**
- The formula for alpha is given by:
\[ \alpha = \frac{\Delta IC}{\Delta IE} \]
- Substituting the values:
\[ \alpha = \frac{7.9 \, \text{mA}}{8.0 \, \text{mA}} = 0.9875 \approx 0.99 \]

3. **Calculate beta (β):**
- The relationship between alpha and beta is given by:
\[ \beta = \frac{\alpha}{1 - \alpha} \]
- Substituting the value of α:
\[ \beta = \frac{0.99}{1 - 0.99} = \frac{0.99}{0.01} = 99 \]

4. **Final Results:**
- The value of alpha (α) is approximately 0.99.
- The value of beta (β) is 99.

### Summary:
- α = 0.99
- β = 99