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A Bohr's hydrogen atom undergoes a trans...

A Bohr's hydrogen atom undergoes a transition `n = 5 to n = 4` and emits a photon of frequency `f`. Frequency of circular motion of electron in `n = 4` orbit is `f_(4)`. The ratio `f//f_(4)` is found to be ----

A

`(18)/(25)`

B

`(16)/(25)`

C

`(9)/(25)`

D

`(8)/(25)`

Text Solution

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The correct Answer is:
A
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