Home
Class 12
PHYSICS
A car, starating from rest, accelerates ...

A car, starating from rest, accelerates at the rate f through a distance S, then continoues at constant speed for time t and then decelerates as the rate `f/2 to come to rest. If the total distance travelled is 15 S, then

A

`S=ft`

B

`S=(1)/(6)ft^(2)`

C

`S=(1)/(2)ft^(2)`

D

`S=(1)/(72)ft^(2)`

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Similar Questions

Explore conceptually related problems

A car, starting from rest, accelerates at the rate f through a distance s, then continues at constant speed for time t and then decelerates at the rate f/ 2 to come to rest. If the total distance travelled is 15 s, then

A car , starting from rest, accelerates at the rate f through a distance S then continues at constant speed for time t and then decelerates at the rate (f)/(2) to come to rest . If the total distance traversed is 15 S , then

A bus starting from rest, accelerates at the rate of f through a distance S, then continues at constant speed for time t and declerates at the rate f/2 to come to rest. If the total distance travelled is 15 S then S =

A car, starting from rest, accelerates at the rate (f) through a distance (S), then continues at constant speed for some time (t) and then decelerates at the rate f//2 to come to rest. If the total distance is 5 S , then prove that S=1/2/ ft^(2) .

A particle starts from rest, accelerates at 2(m)/(s^2) for 10 s and then goes for constant speed for 30 s and then decelerates at 4(m)/(s^2) . Till it stops. What is the distance travelled by it?

A particle starts from rest accelerates at 2 m//s^2 for 10 s and then goes for constant speed for 30 s and then decelerates at 4 m//s^2 till it stops. What is the distance travelled by it.

A particle, starting from rest, moves in a straight line with constant acceleration a_0 for a time interval t_0 .Then is accelerates at a constant rate 2a_0 for time interval 2t_0 .The distance travelled by the particle in time 3t_0 from the starts is S . Then (S)/(a_0t_0^(2) )=

A particles starts from rest and has an acceleration of 2m//s^(2) for 10 sec. After that , it travels for 30 sec with constant speed and then undergoes a retardation of 4m//s^(2) and comes back to rest. The total distance covered by the particle is

A particle starts from rest and has an acceleration of 2 ms^(–2) for 10 s. After that, it travels for 30 s with constant speed and then undergoes a retardation of 4 ms^(–2) and comes to rest. Calculate the total distance covered by the particle.

A car, starting from rest, has a constant acceleration for a time interval t_1 during which it covers a distance In the next time interval the car has a constant retardation and comes to rest after covering a distance in time Which of the following relations is correct?