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The potential energy of a 1 kg particle ...

The potential energy of a 1 kg particle free to move along the x-axis is given by `V(x ) = [(x^4//4) - (x^2//2)J` . The total mechanical energy of the particle is 2J. Then the maximum speed (in m/s) is:

A

`(4)/(sqrt2)`

B

`(1)/(sqrt2)`

C

`(3)/(sqrt2)`

D

2

Text Solution

Verified by Experts

The correct Answer is:
C
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