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Assuming negligible zero error, Find t...

Assuming negligible zero error, Find the thickness of the wire,If In a screw gauge, 5 complete rotations of the screw cause if to move a linear distance of `0.25 cm`. There are `100` circular scale divisions. The thickness of a wire measured by this screw gauge gives a reading of 4 main scale divisions and 30 circular scale divisions.

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To find the thickness of the wire using the screw gauge, we can follow these steps: ### Step 1: Calculate the distance moved by the screw in one complete rotation The problem states that 5 complete rotations cause the screw to move a linear distance of 0.25 cm. Therefore, the distance moved by the screw in one rotation can be calculated as follows: \[ \text{Distance moved in one rotation} = \frac{0.25 \, \text{cm}}{5} = 0.05 \, \text{cm} \] ### Step 2: Calculate the least count of the screw gauge The least count (LC) of the screw gauge can be calculated using the formula: \[ \text{Least Count} = \frac{\text{Distance moved in one rotation}}{\text{Number of circular scale divisions}} \] Given that there are 100 circular scale divisions: \[ \text{Least Count} = \frac{0.05 \, \text{cm}}{100} = 0.0005 \, \text{cm} \] ### Step 3: Calculate the total reading from the screw gauge The thickness of the wire is given by the readings on the screw gauge. We have: - Main Scale Reading (MSR) = 4 main scale divisions - Circular Scale Reading (CSR) = 30 circular scale divisions The total reading can be calculated as: \[ \text{Total Reading} = (\text{MSR} \times \text{Least Count}) + (\text{CSR} \times \text{Least Count}) \] Substituting the values: \[ \text{Total Reading} = (4 \times 0.05) + (30 \times 0.0005) \] Calculating each part: 1. \(4 \times 0.05 = 0.20 \, \text{cm}\) 2. \(30 \times 0.0005 = 0.015 \, \text{cm}\) Now, adding these two results together: \[ \text{Total Reading} = 0.20 \, \text{cm} + 0.015 \, \text{cm} = 0.215 \, \text{cm} \] ### Conclusion The thickness of the wire measured by the screw gauge is: \[ \text{Thickness of the wire} = 0.215 \, \text{cm} \] ---
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