Home
Class 12
PHYSICS
The difference in kinetic energies to ph...

The difference in kinetic energies to photoelectrons emitted from a surface by the light of wavelength `2500 Å and 5000 Å` will be

A

1.61 eV

B

2.47 eV

C

3.96 eV

D

`3.96 xx 10^(-19) eV`

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Similar Questions

Explore conceptually related problems

Find the difference of kinetic energies of photoelectrons emitted from a surface by light of wavelength 2500Å and 5000Å. h=6.62xx10^(-34)Js .

The kinetic energies of the photoelectrons ejected from a metal surface by light of wavelength 2000 Å range from zero to 3.2 xx 10^(-19) Joule. Then find the stopping potential (in V).

Maximum kinetic energy of photoelectrons emitted from a metal surface, when light of wavelength lambda is incident on it, is 1 eV. When a light of wavelength lambda/3 is incident on the surfaces, maximum kinetic energy becomes 4 times. The work function of the metal is

The momentum of the photon of wavelength 5000 Å will be

The kinetic energy of the most energetic photoelectrons emitted from a metal surface is doubled when the wavelength of the incident radiation is reduced from lamda_1 " to " lamda_2 The work function of the metal is

The maximum kinetic energy of photoelectrons emitted from a surface when photons of energy 6 eV fall on it is 4 eV . The stopping potential , in volt is

The photoelectric threshold for a certain metal surface is 330 Å . What is the maximum kinetic energy of the photoelectrons emitted , if radiations of wavelength 1100 Å are used ?

The stopping potential for photoelectrons emitted from a surface illuminated by light wavelength of 5893A is 0.36 V . Calculate the maximum kinetic energy of photoelectrons, the work function of the surface, and the threshold frequency.

If K_(1) and K_(2) are maximum kinetic energies of photoelectrons emitted when light of wavelength lambda_(1) and lambda_(2) respectively are incident on a metallic surface. If lambda_(1)=3lambda_(2) then

If K_(1) and K_(2) are maximum kinetic energies of photoelectrons emitted when light of wavelength lambda_(1) and lambda_(2) respectively are incident on a metallic surface. If lambda_(1)=3lambda_(2) then