Home
Class 12
PHYSICS
Taking the wavelength of first Balmer li...

Taking the wavelength of first Balmer line in hydrogen spectrum (n = 3 to n = 2) as 660 nm, the wavelength of the `2^(nd)` Balmer line (n = 4 to n = 2) will be :

A

889.2 nm

B

488.9 nm

C

388.9 nm

D

642.7 nm

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Similar Questions

Explore conceptually related problems

Calculate the wavelength of the first line in the Balmer series of hydrogen spectrum.

Calculate the wavelength of the first line in the Balmer series of hydrogen spectrum

If the wavelength of first member of Balmer series of hydrogen spectrum is 6564 A^(@) . The wavelength of second member of Balmer series will be :

If the wavelength of the first member of Balmer series of hydrogen spectrum is 6563Å , then the wavelength of second member of Balmer series will be

What transition in the hydrogen spectrum would have the same wavelength as the Balmer transition, n = 4 to n = 2 of He+ spectrum?

If the wavelength of the first line of the Balmer series of hydrogen is 6561 Å , the wavelngth of the second line of the series should be

If the wavelength of the first line of the Balmer series of hydrogen is 6561 Å , the wavelngth of the second line of the series should be

The line with smallest wavelength in the Balmer series in the hydrogen spectrum will have the frequency :-

The Wavelength of first member of Balmer series in hydrogen spectrum is lambda . Calculate the wavelength of first member of Lymen series in the same spectrum

The wavelength of the third line of the Balmer series for a hydrogen atom is -