Write the IUPAC name of the following compound
`OHC - CH_2-CH_2-overset(CH_2-CHO)overset(|)(CH)-CH_2-CHO`

Options

A. 3 - (oxomethyl) hexane - 1, 6 - dial
B. 3 - methylhexane -1,3,6 - trial
C. 3 - (methylformyl) hexane -1, 6 - dial
D. 3 - (formylmethyl) hexane -1, 6 - dial

Answer

To determine the IUPAC name of the given compound, we will follow these steps:

### Step 1: Identify the longest carbon chain
First, we need to identify the longest continuous carbon chain in the compound. The structure given has a total of 6 carbon atoms in the main chain.

### Step 2: Number the carbon chain
Next, we will number the carbon chain. We will start numbering from the end nearest to the first substituent (aldehyde group). In this case, we can number the chain from the right side to give the aldehyde groups the lowest possible numbers.

### Step 3: Identify the substituents
The compound has two aldehyde groups (–CHO) and one formyl methyl group (–CH2CHO). The formyl methyl group is attached at carbon 3 of the main chain.

### Step 4: Assign locants to the substituents
The aldehyde groups are located at carbon 1 and carbon 6. Therefore, we will assign the locants as follows:
- Aldehyde at carbon 1
- Aldehyde at carbon 6
- Formyl methyl group at carbon 3

### Step 5: Write the IUPAC name
Now we can compile all the information to write the IUPAC name. The main chain has 6 carbon atoms, which is hexane. Since there are two aldehyde groups, we will use the prefix "di-" and the suffix "al" for aldehydes. Thus, the name will be:
- 3-formyl methyl hexane-1,6-dial

### Final IUPAC Name
The final IUPAC name of the compound is **3-formyl methyl hexane-1,6-dial**.

---