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What is the binding energy (in J/mol or ...

What is the binding energy (in J/mol or KJ/mol) of an electron in a metal. Whose threshold frequency for photon electron is `2.5xx10^(14)s^(-1)` ?

A

99.38 KJ/mol

B

`1.66 xx10^(-19)` J/ mol

C

`2.75 xx10^(-43)` J/mol

D

`7.22xx10^(17)` kJ/mol

Text Solution

AI Generated Solution

The correct Answer is:
To determine the binding energy of an electron in a metal given the threshold frequency, we can follow these steps: ### Step 1: Identify the given values - Threshold frequency (ν) = \(2.5 \times 10^{14} \, \text{s}^{-1}\) - Planck's constant (h) = \(6.626 \times 10^{-34} \, \text{J s}\) ### Step 2: Calculate the work function (φ) The work function (φ) can be calculated using the formula: \[ \phi = h \nu \] Substituting the values: \[ \phi = (6.626 \times 10^{-34} \, \text{J s}) \times (2.5 \times 10^{14} \, \text{s}^{-1}) \] Calculating this gives: \[ \phi = 1.6565 \times 10^{-19} \, \text{J} \] ### Step 3: Convert the work function to kJ/mol To convert the work function from joules to kilojoules per mole, we use Avogadro's number (\(N_A = 6.022 \times 10^{23} \, \text{mol}^{-1}\)): \[ \text{Binding Energy (in J/mol)} = \phi \times N_A \] Substituting the values: \[ \text{Binding Energy} = (1.6565 \times 10^{-19} \, \text{J}) \times (6.022 \times 10^{23} \, \text{mol}^{-1}) \] Calculating this gives: \[ \text{Binding Energy} \approx 99.38 \, \text{kJ/mol} \] ### Final Answer The binding energy of the electron in the metal is approximately **99.38 kJ/mol**. ---
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