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Compare the boiling points of 1. n - b...

Compare the boiling points of
1. n - butylamine
2. n - butyl alcohol
3. pentane

A

`2 gt 3 gt 1`

B

`2 gt 1 gt 3`

C

`1 gt 3 gt 2`

D

`3 gt 2 gt 1 `

Text Solution

AI Generated Solution

The correct Answer is:
To compare the boiling points of n-butylamine, n-butyl alcohol, and pentane, we need to analyze the molecular structures and the types of intermolecular forces present in each compound. ### Step 1: Identify the Structures 1. **n-butylamine (C4H11N)**: This molecule consists of a butyl group (four carbon atoms) attached to an amine group (NH2). - Structure: CH3-CH2-CH2-CH2-NH2 2. **n-butyl alcohol (C4H10O)**: This molecule consists of a butyl group attached to a hydroxyl group (OH). - Structure: CH3-CH2-CH2-CH2-OH 3. **Pentane (C5H12)**: This is a straight-chain alkane with five carbon atoms. - Structure: CH3-CH2-CH2-CH2-CH3 ### Step 2: Determine Intermolecular Forces - **n-butylamine**: Can form hydrogen bonds due to the presence of the NH2 group. Hydrogen bonds are relatively strong intermolecular forces. - **n-butyl alcohol**: Can also form hydrogen bonds due to the presence of the OH group. The oxygen atom is more electronegative than nitrogen, leading to stronger hydrogen bonding. - **Pentane**: Being a non-polar molecule, it only exhibits weak van der Waals forces (London dispersion forces), which are significantly weaker than hydrogen bonds. ### Step 3: Compare Boiling Points - **Boiling Point of n-butyl alcohol**: The strongest intermolecular forces are present due to hydrogen bonding with oxygen, leading to the highest boiling point among the three. - **Boiling Point of n-butylamine**: The hydrogen bonding is present but is weaker than that of n-butyl alcohol because nitrogen is less electronegative than oxygen. Thus, n-butylamine has a lower boiling point than n-butyl alcohol but higher than pentane. - **Boiling Point of pentane**: With only weak van der Waals forces, pentane has the lowest boiling point of the three compounds. ### Conclusion The order of boiling points from highest to lowest is: 1. n-butyl alcohol (highest boiling point) 2. n-butylamine 3. Pentane (lowest boiling point) Thus, the correct order is: **n-butyl alcohol > n-butylamine > pentane**.
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