Home
Class 12
CHEMISTRY
The electronic configuration of a diposi...

The electronic configuration of a dipositive ion `M^(2+)` is 2, 8, 14 and its mass number is 56. The number of netrons present is

A

24

B

30

C

32

D

56

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding the number of neutrons in the dipositive ion \( M^{2+} \) with an electronic configuration of 2, 8, 14 and a mass number of 56, we can follow these steps: ### Step 1: Determine the total number of electrons in the ion The electronic configuration given is 2, 8, 14. To find the total number of electrons, we add these numbers together: \[ \text{Total electrons} = 2 + 8 + 14 = 24 \] ### Step 2: Determine the number of protons Since \( M^{2+} \) is a dipositive ion, it has lost 2 electrons. Therefore, the number of protons (which is equal to the number of electrons in a neutral atom) can be calculated as follows: \[ \text{Number of protons} = \text{Total electrons} + 2 = 24 + 2 = 26 \] ### Step 3: Use the mass number to find the number of neutrons The mass number (A) is given as 56. The mass number is the sum of the number of protons (Z) and the number of neutrons (N): \[ \text{Mass number} = \text{Number of protons} + \text{Number of neutrons} \] Substituting the known values: \[ 56 = 26 + N \] ### Step 4: Solve for the number of neutrons Rearranging the equation to find \( N \): \[ N = 56 - 26 = 30 \] ### Conclusion The number of neutrons present in the dipositive ion \( M^{2+} \) is 30.
Promotional Banner

Similar Questions

Explore conceptually related problems

The electronic configuration of a dipositive ion M2+ is 2,8,14 and its mass number is 56. What is the number of neutrons present?

The electronic configuration of Ti^(2+) ion is ………….

The electronic configuration of gadolinium (Atomic number 64) is

What is the electronic configuration of O^(2-) ion?

the correct electronic configuration of Cu^(2+) ion is

Atomic number of an ion is the same as the number of electrons present in it.

The electronic configuration of an element 'X' is 2,8,8,2. Write its (i) group number, (ii) period number and (iii) the number of valence electrons in its atom. Justify your answer in each case.

The electronic configuration of an ion M^(2+) is 1s^(2)2s^(2)2p^(6)3s^(2)3p^(6)3d^(6) and the atomic weight of M is 56. The number of neutrons in the nucleus of M^(2+) is

Write electronic configuration of Fe^(2+) and Fe^(3+) ions. Which of these has more number of unpaired electrons? Atomic no. of Fe is 26 .

An element 'X' has its electronic configuration of 'K' shell is (n-5)s^(2) and it has total number of electrons in its outermost, penultimate and antipenultimate shell are 2,8 and 25 respectively then find out total number of unpaired electrons in element 'X' in their ground state.