The reaction of benzoyl chloride with phenol in presence of NaOH is called

Options

A. Schotten - Baumann reaction
B. Bouveault - Blank reduction
C. Clemmensen reduction
D. Stephen's reduction

Answer

To solve the question regarding the reaction of benzoyl chloride with phenol in the presence of NaOH, we can break it down into the following steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactants in this reaction are benzoyl chloride (C6H5COCl) and phenol (C6H5OH).

2. **Understand the Role of NaOH**:
- Sodium hydroxide (NaOH) acts as a base in this reaction. It deprotonates the hydroxyl group (-OH) of phenol, making it a more reactive nucleophile.

3. **Nucleophilic Attack**:
- The deprotonated phenol (now a phenoxide ion, C6H5O-) attacks the carbonyl carbon of benzoyl chloride. This is a nucleophilic substitution reaction where the nucleophile (phenoxide ion) attacks the electrophile (carbonyl carbon of benzoyl chloride).

4. **Formation of the Intermediate**:
- The nucleophilic attack leads to the formation of a tetrahedral intermediate, which subsequently collapses.

5. **Elimination of HCl**:
- The tetrahedral intermediate collapses, resulting in the elimination of hydrochloric acid (HCl) and forming the final product.

6. **Identify the Product**:
- The product formed from this reaction is phenyl benzoate (C6H5COOC6H5).

7. **Name of the Reaction**:
- This reaction is specifically known as the Schotten-Baumann reaction, which is a method for acylating phenols using acid chlorides in the presence of a base.

### Final Answer:
The reaction of benzoyl chloride with phenol in the presence of NaOH is called the **Schotten-Baumann reaction**.

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