Pick out the incorrect statement regarding `H_2O_2`.

Options

A. `H_2O_2` is kept in waxlined bottle
B. `H_2O_2` acts both as oxidizing and reducing agent
C. It is not possible to determine its boiling point at atmospheric pressure
D. `H_2O_2` does not react with acidified `KMnO_4`

Answer

To determine the incorrect statement regarding \( H_2O_2 \) (hydrogen peroxide), we will analyze each statement provided in the question step by step.

### Step 1: Analyze the first statement
**Statement:** \( H_2O_2 \) is kept in wax-lined bottles.

**Analysis:** This statement is true. Hydrogen peroxide is highly reactive and decomposes in the presence of light, forming water and oxygen. Therefore, it is stored in dark or wax-lined bottles to prevent decomposition.

### Step 2: Analyze the second statement
**Statement:** \( H_2O_2 \) acts both as an oxidizing and reducing agent.

**Analysis:** This statement is also true. \( H_2O_2 \) can act as an oxidizing agent by gaining electrons (undergoing reduction) and as a reducing agent by losing electrons (undergoing oxidation).

### Step 3: Analyze the third statement
**Statement:** It is not possible to determine its boiling point at atmospheric pressure.

**Analysis:** This statement is true as well. Due to its high reactivity, \( H_2O_2 \) decomposes readily, making it difficult to determine a precise boiling point under atmospheric pressure.

### Step 4: Analyze the fourth statement
**Statement:** \( H_2O_2 \) does not react with acidified \( KMnO_4 \).

**Analysis:** This statement is incorrect. \( H_2O_2 \) does react with acidified \( KMnO_4 \). In acidic conditions, \( KMnO_4 \) is reduced by \( H_2O_2 \), leading to the formation of \( Mn^{2+} \), oxygen gas, and water. Therefore, this statement is indeed false.

### Conclusion
The incorrect statement regarding \( H_2O_2 \) is that it does not react with acidified \( KMnO_4 \). Thus, the answer is:

**Answer:** Option D - \( H_2O_2 \) does not react with acidified \( KMnO_4 \).

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