The hydrolysis of 1 mol of chloroform requires

Options

A. 1 mol of KOH
B. 2 mol of KOH
C. 3 mol of KOH
D. 4 mol of KOH

Answer

To solve the question regarding the hydrolysis of 1 mole of chloroform (CSCl3), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reaction**:
Chloroform (CSCl3) undergoes hydrolysis in the presence of potassium hydroxide (KOH). The reaction involves the substitution of chlorine atoms by hydroxyl (OH) groups.

2. **Determine the Number of KOH Molecules Required**:
Chloroform has three chlorine atoms. Each chlorine atom will be replaced by a hydroxyl group from KOH. Therefore, we need 3 moles of KOH to replace the 3 Cl atoms.

3. **Formation of Intermediate Product**:
After the substitution of the three Cl atoms, we form an intermediate compound (HCOH) which can further react.

4. **Dehydration Reaction**:
The intermediate product (HCOH) can lose a water molecule (H2O) when heated, leading to the formation of a carboxylic acid derivative (SC=O).

5. **Final Reaction with KOH**:
The product formed can react with one more mole of KOH to form potassium formate (SC=O O^- K^+).

6. **Total KOH Required**:
Adding the moles of KOH used:
- 3 moles for the initial substitution of Cl atoms
- 1 mole for the final reaction with the intermediate product
- Total = 3 + 1 = 4 moles of KOH.

### Conclusion:
The hydrolysis of 1 mole of chloroform requires **4 moles of KOH**.

### Final Answer:
The correct option is **4 moles of KOH**.

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