Reaction between diethyl cadmium and acetyl chloride lead to the formation of

Options

A. dimethyl ketone
B. ethyl methyl ketone
C. diethyl ketone
D. acetaldehyde

Answer

To solve the problem of what product is formed when diethyl cadmium reacts with acetyl chloride, we can follow these steps:

### Step 1: Identify the Reactants
- **Diethyl Cadmium**: The chemical formula is \( \text{C}_2\text{H}_5\text{Cd}\text{C}_2\text{H}_5 \) or \( \text{(C}_2\text{H}_5)_2\text{Cd} \).
- **Acetyl Chloride**: The chemical formula is \( \text{CH}_3\text{COCl} \).

### Step 2: Understand the Nature of the Reaction
Diethyl cadmium acts as a nucleophile due to the presence of the carbon-metal bond (C-Cd). In this case, the carbon atom attached to cadmium has a partial negative charge, making it a good nucleophile.

### Step 3: Nucleophilic Attack
The nucleophilic carbon from diethyl cadmium will attack the electrophilic carbon in acetyl chloride. The carbonyl carbon in acetyl chloride is electron-deficient due to the electronegativity of the oxygen atom.

### Step 4: Reaction Mechanism
1. The nucleophilic carbon from diethyl cadmium attacks the carbonyl carbon of acetyl chloride.
2. This leads to the formation of a tetrahedral intermediate.
3. The chlorine atom leaves, resulting in the formation of a ketone.

### Step 5: Identify the Product
The product formed from this reaction is **ethyl methyl ketone**, which has the structure \( \text{CH}_3\text{CO}\text{C}_2\text{H}_5 \).

### Conclusion
Thus, when diethyl cadmium reacts with acetyl chloride, the product formed is **ethyl methyl ketone**.

### Final Answer
The correct answer is **ethyl methyl ketone** (Option 2).

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