Anaerobic respiration of 1 mol of glucose produces.

Options

A. `4CO_2+4H_2O`
B. `2C_2H_5OH+2CO_2`
C. `CH_3CH_2OH+CH_3OH+CO_2`
D. `CH_3OH + CO_2+H_2O`

Answer

To solve the question regarding the anaerobic respiration of 1 mole of glucose, we can break down the process step by step:

### Step 1: Understand Anaerobic Respiration
Anaerobic respiration occurs in the absence of oxygen. It starts with the glycolysis process where glucose is broken down.

**Hint:** Remember that anaerobic respiration is different from aerobic respiration, which requires oxygen.

### Step 2: Glycolysis
In glycolysis, 1 mole of glucose (C6H12O6) is converted into 2 moles of pyruvate. During this process, 2 ATP molecules are also produced.

**Hint:** Glycolysis is the first step in both aerobic and anaerobic respiration and occurs in the cytoplasm.

### Step 3: Fate of Pyruvate in Anaerobic Conditions
In anaerobic conditions, the pyruvate produced from glycolysis does not enter the mitochondria. Instead, it undergoes fermentation.

**Hint:** Think about what happens to pyruvate when oxygen is not available.

### Step 4: Types of Fermentation
There are two main types of fermentation:
1. **Lactic Acid Fermentation:** Occurs in humans and some bacteria, producing lactic acid.
2. **Alcoholic Fermentation:** Occurs in yeast and some plants, producing ethanol and carbon dioxide.

**Hint:** Identify which type of fermentation is relevant based on the organism (humans vs. yeast/plants).

### Step 5: Products of Anaerobic Respiration
For the question, since we are not considering lactic acid (as the question does not mention it), we focus on alcoholic fermentation, which produces:
- 2 moles of ethanol (C2H5OH)
- 2 moles of carbon dioxide (CO2)

**Hint:** Recall the balanced equation for alcoholic fermentation to confirm the products.

### Conclusion
Thus, the anaerobic respiration of 1 mole of glucose produces 2 moles of ethanol and 2 moles of carbon dioxide.

**Final Answer:** 2 moles of ethanol and 2 moles of carbon dioxide.