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The enthalpy change for a given reaction...

The enthalpy change for a given reaction at `298 K` is `-x cal mol^(-1)`. If the reaction occurs spontaneously at `298 K`, the entropy change at that temperature

A

can be negative , but numerically larger than x/298 cal `"mol"^(-1) K^(-1)`

B

can be negative , but numerically smaller than x/298 cal `"mol"^(-1) K^(-1)`

C

cannot be negative

D

cannot be positive

Text Solution

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The correct Answer is:
B
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