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1.2 L of hydrogen and 1.12 L of chlorine...

1.2 L of hydrogen and 1.12 L of chlorine are reacted. The composition by volume of mixture is

A

0.08 L of `H_2` and 2.24 L of HCl

B

2.24 L of `H_2` and 2.24 L of HCl

C

0.08 L of `Cl_2` and 20.8 L of HCl

D

22.4 L of `Cl_2` and 20.8 L of HCl

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to determine the composition by volume of the mixture after the reaction between hydrogen (H₂) and chlorine (Cl₂) has taken place. Here’s a step-by-step solution: ### Step 1: Write the balanced chemical equation The reaction between hydrogen and chlorine can be represented as: \[ \text{H}_2 + \text{Cl}_2 \rightarrow 2 \text{HCl} \] This equation shows that 1 volume of hydrogen reacts with 1 volume of chlorine to produce 2 volumes of hydrochloric acid (HCl). ### Step 2: Identify the initial volumes of reactants We have: - Volume of hydrogen (H₂) = 1.2 L - Volume of chlorine (Cl₂) = 1.12 L ### Step 3: Determine the limiting reagent From the balanced equation, we see that hydrogen and chlorine react in a 1:1 ratio. Therefore, we need to determine which reactant will be completely consumed first. - For 1.12 L of Cl₂, we would need 1.12 L of H₂ to completely react with it. - We have 1.2 L of H₂ available, which is more than enough to react with 1.12 L of Cl₂. Thus, **Cl₂ is the limiting reagent**. ### Step 4: Calculate the amount of H₂ consumed Since Cl₂ is the limiting reagent, all of it will be consumed: - Volume of Cl₂ reacted = 1.12 L - According to the stoichiometry of the reaction, 1.12 L of Cl₂ will react with 1.12 L of H₂. ### Step 5: Calculate the remaining volume of H₂ Initial volume of H₂ = 1.2 L Volume of H₂ consumed = 1.12 L Remaining volume of H₂: \[ \text{Remaining H}_2 = 1.2 \, \text{L} - 1.12 \, \text{L} = 0.08 \, \text{L} \] ### Step 6: Calculate the volume of HCl produced From the balanced equation, for every 1 volume of Cl₂ consumed, 2 volumes of HCl are produced. Therefore: - Volume of HCl produced = 2 × Volume of Cl₂ reacted \[ \text{Volume of HCl} = 2 \times 1.12 \, \text{L} = 2.24 \, \text{L} \] ### Step 7: Determine the final composition by volume After the reaction, we have: - Remaining H₂ = 0.08 L - Produced HCl = 2.24 L Thus, the total composition by volume of the mixture is: - H₂: 0.08 L - HCl: 2.24 L ### Final Answer The composition by volume of the mixture is: - 0.08 L of H₂ and 2.24 L of HCl.
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