The hybridisation of central metel ion and shape of Wilkinson's catalyst is

Options

A. `dsp^2` , square planar
B. `sp^3` , tetrahedral
C. `d^2sp^3` , octahedral
D. `sp^3d`, trigonal bipyrmidal

Answer

To determine the hybridization of the central metal ion and the shape of Wilkinson's catalyst, we can follow these steps:

### Step 1: Identify the central metal ion
Wilkinson's catalyst is typically represented by the formula [RhCl(PPh3)3]. Here, Rh (rhodium) is the central metal ion.

**Hint:** Look for the metal ion in the chemical formula of the catalyst.

### Step 2: Determine the coordination number
In Wilkinson's catalyst, the rhodium ion is coordinated to three triphenylphosphine (PPh3) ligands and one chloride (Cl) ligand. This gives a total of four ligands around the central metal ion.

**Hint:** Count the number of ligands attached to the central metal ion to find the coordination number.

### Step 3: Determine the hybridization
For a coordination number of 4, the possible hybridizations are sp³ or dsp². However, since the geometry of Wilkinson's catalyst is square planar, the hybridization is dsp².

**Hint:** Recall that square planar geometry corresponds to dsp² hybridization.

### Step 4: Identify the shape of the molecule
With dsp² hybridization, the arrangement of the ligands around the central metal ion leads to a square planar shape.

**Hint:** Remember that the geometry can often be inferred from the hybridization and the number of ligands.

### Conclusion
Thus, the hybridization of the central metal ion in Wilkinson's catalyst is dsp², and the shape of the catalyst is square planar.

**Final Answer:** The hybridization is dsp² and the shape is square planar.

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