Aniline can be distinguished from methyl amine by its reaction with

Options

A. p - toluene sulphonyl chloride /KOH
B. (i) `NaNO_2//HCl,0-5^@C`
(ii) alkaline `beta` - naphthol
C. Sn/HCl
D. Acetyl choride

Answer

To distinguish between aniline and methyl amine, we can utilize their different reactions with certain reagents. Here’s a step-by-step breakdown of the solution:

### Step 1: Identify the Structures
- **Aniline**: C6H5NH2 (an amine attached to a benzene ring)
- **Methyl Amine**: CH3NH2 (a simple primary amine)

### Step 2: Analyze the Given Options
We have four options to consider for distinguishing between aniline and methyl amine:
1. Para-toluene sulfonyl chloride and potassium hydroxide
2. NaNO2 and HCl at 0-5 °C followed by alkaline beta-naphthol
3. SNHCl
4. Acetyl chloride

### Step 3: Evaluate Each Option
1. **Para-toluene sulfonyl chloride and potassium hydroxide**:
- This reagent is used primarily for distinguishing between secondary and tertiary amines. Both aniline and methyl amine are primary amines, so this option will not provide a distinguishing test. **(Incorrect)**

2. **NaNO2 and HCl at 0-5 °C followed by alkaline beta-naphthol**:
- Aniline reacts with NaNO2 and HCl to form benzene diazonium chloride, which can further react with beta-naphthol to produce an orange-red azo dye, indicating the presence of aniline.
- Methyl amine, however, will not form a stable diazonium salt and will instead yield a colorless product (an alcohol). This makes this option the correct choice for distinguishing between the two amines. **(Correct)**

3. **SNHCl**:
- This is a reducing agent that reduces nitro groups to amines. Since we are dealing with primary amines already, this option will not provide any distinguishing test. **(Incorrect)**

4. **Acetyl chloride**:
- Both aniline and methyl amine will react with acetyl chloride to form acetamides. The products will be colorless and will not provide a distinguishing test. **(Incorrect)**

### Conclusion
The only correct option that allows for the distinction between aniline and methyl amine is **Option 2: NaNO2 and HCl followed by alkaline beta-naphthol**. Aniline produces a colored dye, while methyl amine does not.

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