the reaction of `C_6H_5O^(-)Na^(+) and CO_2` at 6 atm 400 K, followed by addition of aq.acid is called

Options

A. Reimer - Tiemann reaction
B. Kolbe reaction
C. Wurtz reaction
D. Cannizzaro reaction

Answer

To solve the question regarding the reaction of \( C_6H_5O^{-}Na^{+} \) with \( CO_2 \) at 6 atm and 400 K, followed by the addition of aqueous acid, we can break it down step by step.

### Step-by-Step Solution:

1. **Identify the Reactants**:
The reactants in this reaction are sodium phenoxide (\( C_6H_5O^{-}Na^{+} \)) and carbon dioxide (\( CO_2 \)).

2. **Understand the Reaction Conditions**:
The reaction occurs under high pressure (6 atm) and elevated temperature (400 K). These conditions are typically used to facilitate the reaction between sodium phenoxide and carbon dioxide.

3. **Reaction Mechanism**:
When sodium phenoxide reacts with carbon dioxide, it undergoes a carboxylation reaction. The phenoxide ion (\( C_6H_5O^{-} \)) acts as a nucleophile and attacks the electrophilic carbon of \( CO_2 \). This results in the formation of a carboxylate intermediate.

4. **Formation of Salicylic Acid**:
After the carboxylation, the intermediate can be protonated by the addition of aqueous acid. This protonation leads to the formation of salicylic acid (\( C_6H_4(OH)(COOH) \)), which contains both a hydroxyl group and a carboxylic acid group.

5. **Name the Reaction**:
The entire process, which involves the reaction of sodium phenoxide with carbon dioxide followed by acidification, is known as **Kolbe's reaction** (or Colby's reaction). This reaction is significant in organic chemistry for synthesizing aromatic carboxylic acids.

### Final Answer:
The reaction of \( C_6H_5O^{-}Na^{+} \) and \( CO_2 \) at 6 atm and 400 K, followed by the addition of aqueous acid, is called **Kolbe's reaction**.