The following reaction `R-CH_2CH_2overset(+)N(CH_3)_3OH^(-)` is called `overset(Delta)rarrRCH=CH_2+N(CH_3)_3+H_2O`

Options

A. Hoffmann - bromamide reaction
B. Cope elimination
C. Hoffmann elimination
D. Beckmann rearrangement

Answer

To solve the question regarding the reaction \( R-CH_2CH_2^+\text{N(CH}_3)_3\text{OH}^-\) leading to \( RCH=CH_2 + \text{N(CH}_3)_3 + H_2O \), we need to identify the type of reaction taking place.

### Step-by-Step Solution:

1. **Identify the Reactants and Products**:
- The reactants are \( R-CH_2CH_2^+\text{N(CH}_3)_3\text{OH}^-\) and the products are \( RCH=CH_2 + \text{N(CH}_3)_3 + H_2O \).

2. **Understanding the Reaction Mechanism**:
- The presence of \( OH^- \) indicates that a base is involved in the reaction. This base will abstract a proton (H) from the carbon adjacent to the nitrogen.

3. **Proton Abstraction**:
- The base \( OH^- \) abstracts a hydrogen atom from the \( R-CH_2CH_2 \) part, leading to the formation of a double bond between the two carbon atoms (alkene formation).

4. **Formation of Products**:
- After the proton abstraction, the nitrogen (which is part of the trimethylamine) will stabilize by accepting the electrons from the bond that was broken, resulting in the formation of trimethylamine \( \text{N(CH}_3)_3 \) and water \( H_2O \).

5. **Identifying the Type of Reaction**:
- This reaction is classified as a **Hofmann elimination reaction**. In Hofmann elimination, a quaternary ammonium salt is converted into an alkene, and this process involves the loss of a water molecule.

6. **Conclusion**:
- Therefore, the type of reaction taking place is **Hofmann elimination**.

### Final Answer:
The reaction is a **Hofmann elimination reaction**.

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