Identify the final product `(Z)` in the following sequence of reactions. `CH_3NH_2overset(CH_3l" Excess")rarr(X) overset(AgOH)rarr(Y)overset(Delta)rarr(Z)+ CH_3OH`

Options

A. `CH_3CH_2CH_2NH_2`
B. `(CH_3)_3N`
C. `(CH_3)_2NH`
D. `(CH_3)_4overset(+)NOH^(-)`

Answer

To determine the final product \( Z \) in the given sequence of reactions, we will follow the steps outlined in the problem statement.

### Step 1: Reaction of \( CH_3NH_2 \) with \( CH_3I \)
1. **Starting Material**: \( CH_3NH_2 \) (methylamine)
2. **Reagent**: \( CH_3I \) (methyl iodide)
3. **Reaction**: The nitrogen in methylamine attacks the carbon in methyl iodide, leading to the formation of a methylated amine. The iodide ion \( I^- \) is released.
4. **Product \( X \)**: The product formed is \( CH_3N(CH_3)_2 \) (dimethylamine).

### Step 2: Reaction of \( X \) with \( AgOH \)
1. **Starting Material**: \( X = CH_3N(CH_3)_2 \)
2. **Reagent**: \( AgOH \)
3. **Reaction**: The \( AgOH \) will react with the iodide ion present in \( X \) to form \( AgI \) (which precipitates out) and will leave us with a quaternary ammonium compound.
4. **Product \( Y \)**: The product formed is \( CH_3N^+(CH_3)_2(OH^-) \) (a quaternary ammonium hydroxide).

### Step 3: Heating \( Y \) to form \( Z \)
1. **Starting Material**: \( Y = CH_3N^+(CH_3)_2(OH^-) \)
2. **Reaction**: Upon heating, the hydroxide group can lead to the elimination of \( CH_3OH \) (methanol) and form a stable product.
3. **Product \( Z \)**: The final product formed is \( (CH_3)_3N \) (trimethylamine).

### Final Product
Thus, the final product \( Z \) is \( (CH_3)_3N \) (trimethylamine).

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