Which of the following compounds will give acetic acid with `KMnO_(4)//H^(o+)//Delta`:

Options

A. `CH_3-CHO`
B. `CH_3-CH=CH-CH_3`
C. `CH_3-C-=C-CH_3`
D. All of these

Answer

To determine which compounds will yield acetic acid (CH3COOH) when treated with KMnO4 in the presence of H+ and heat, we need to analyze the oxidation reactions of the given compounds.

### Step-by-Step Solution:

1. **Identify the Compounds**:
We need to consider the compounds provided in the question. Let's assume the compounds are:
- (a) CH3CHO (acetaldehyde)
- (b) CH3CH=CHCH3 (symmetrical alkene)
- (c) CH3C≡CCH3 (symmetrical alkyne)

2. **Understanding the Oxidizing Agent**:
KMnO4 is a strong oxidizing agent that can oxidize aldehydes to carboxylic acids, and it can also oxidize alkenes and alkynes to carboxylic acids.

3. **Oxidation of Acetaldehyde (CH3CHO)**:
- When acetaldehyde is treated with KMnO4, it gets oxidized to acetic acid:
\[ CH3CHO + [O] \rightarrow CH3COOH \]
- Thus, CH3CHO will give acetic acid.

4. **Oxidation of Symmetrical Alkene (CH3CH=CHCH3)**:
- This symmetrical alkene can be oxidized by KMnO4 to yield two moles of acetic acid:
\[ CH3CH=CHCH3 + [O] \rightarrow 2 CH3COOH \]
- Therefore, this compound will also give acetic acid.

5. **Oxidation of Symmetrical Alkyne (CH3C≡CCH3)**:
- The symmetrical alkyne can also be oxidized by KMnO4 to form two moles of acetic acid:
\[ CH3C≡CCH3 + [O] \rightarrow 2 CH3COOH \]
- Hence, this compound will also yield acetic acid.

6. **Conclusion**:
- All the compounds listed (acetaldehyde, symmetrical alkene, and symmetrical alkyne) will give acetic acid when treated with KMnO4, H+, and heat.

### Final Answer:
All of the compounds will give acetic acid with KMnO4/H+/Δ.

---