In the given reaction `CH_3-underset(CH_3)underset(|)overset(CH_3)overset(|)C-CH_2-Broverset(Delta)rarr[X]`
[X] will be

Options

A. `CH_3-underset(CH_3)underset(|)(CH)-CH=CH_2`
B. `CH_3-underset(CH_3)underset(|)C=CH-CH_3`
C. `CH_3-CH=CH-CH_3`
D. `CH_3-CH_2-CH=CH_2`

Answer

To solve the given reaction and identify the product [X], we can follow these steps:

### Step 1: Identify the Reactant
The reactant is a tertiary alkyl halide, specifically a compound with a bromine atom (Br) attached to a carbon that is also bonded to three other carbon atoms (CH3 groups). The structure can be represented as:
```
CH3
|
CH3-C-CH2-Br
```

### Step 2: Understand the Reaction Type
Since we are heating the compound, we can expect an elimination reaction to occur. In elimination reactions, a leaving group (in this case, bromine) is removed, resulting in the formation of a double bond.

### Step 3: Remove the Leaving Group
When bromine (Br) leaves, it generates a carbocation (a positively charged carbon atom). The reaction can be illustrated as:
```
CH3
|
CH3-C^+ - CH2
```
Here, the positive charge is on the carbon that was originally bonded to bromine.

### Step 4: Stabilize the Carbocation
The carbocation formed is unstable. To stabilize it, we can use hyperconjugation. The adjacent CH3 groups can donate electron density to the positively charged carbon, which helps stabilize the carbocation.

### Step 5: Shift the Positive Charge
The positive charge can shift to a more stable position. In this case, the positive charge can move to the carbon that is bonded to two CH3 groups, leading to a more stable tertiary carbocation:
```
CH3
|
CH3-C^+ - CH2
```

### Step 6: Eliminate a Hydrogen Atom
To form a double bond, we need to remove a hydrogen atom from the adjacent carbon (the one that is not bonded to bromine). This results in the formation of a double bond between the carbon atoms:
```
CH3
|
CH3-C=CH2
```

### Step 7: Write the Final Product
The final product [X] after the elimination reaction is:
```
CH3
|
CH3-C=CH2
```
This compound is an alkene, specifically propene.

### Conclusion
Thus, the product [X] formed from the reaction is propene (C3H6).

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