Which of the following chemical regent can provide distinctin between the two ionsisation isomers of the formula `Co(NH_3)_5BrSO_4` ?

Options

A. `BaCl_2` solution
B. dil. HCl
C. dil. `H_2SO_4`
D. Fenton's reagents

Answer

To solve the question regarding the distinction between the two ionization isomers of the formula \( \text{Co(NH}_3\text{)}_5\text{BrSO}_4 \), we will follow these steps:

### Step 1: Identify the Ionization Isomers
The compound \( \text{Co(NH}_3\text{)}_5\text{BrSO}_4 \) can exist in two ionization forms:
1. **Isomer 1**: \( \text{Co(NH}_3\text{)}_5\text{Br}^{2+} \) and \( \text{SO}_4^{2-} \)
2. **Isomer 2**: \( \text{Co(NH}_3\text{)}_5\text{SO}_4^{+} \) and \( \text{Br}^{-} \)

### Step 2: Determine the Ions Formed
- For **Isomer 1**, the ions formed in solution are:
- \( \text{Co(NH}_3\text{)}_5\text{Br}^{2+} \)
- \( \text{SO}_4^{2-} \)

- For **Isomer 2**, the ions formed in solution are:
- \( \text{Co(NH}_3\text{)}_5\text{SO}_4^{+} \)
- \( \text{Br}^{-} \)

### Step 3: Choose a Reagent for Distinction
To distinguish between these two ionization isomers, we need a reagent that reacts differently with the ions produced by each isomer.

### Step 4: Use Barium Chloride (BaCl2)
When we add \( \text{BaCl}_2 \) to the solutions:
- For **Isomer 1**: The sulfate ion \( \text{SO}_4^{2-} \) will react with \( \text{Ba}^{2+} \) ions to form a white precipitate of \( \text{BaSO}_4 \).

- For **Isomer 2**: The bromide ion \( \text{Br}^{-} \) does not form a precipitate with \( \text{Ba}^{2+} \), as \( \text{BaBr}_2 \) is soluble in water.

### Step 5: Conclusion
Thus, the addition of \( \text{BaCl}_2 \) allows us to distinguish between the two ionization isomers:
- A white precipitate indicates the presence of Isomer 1.
- No precipitate indicates the presence of Isomer 2.

### Final Answer
The reagent that can provide distinction between the two ionization isomers of \( \text{Co(NH}_3\text{)}_5\text{BrSO}_4 \) is **Barium Chloride (BaCl2)**.

---