Home
Class 12
CHEMISTRY
Number of stereoisomers of the given com...

Number of stereoisomers of the given compound is
`CH_(3)-CH=CH-underset(OH)underset(|)(CH)-CH_(3)`

A

2

B

4

C

3

D

6

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Similar Questions

Explore conceptually related problems

Total number of stereoisomers of the compound CH_(3)-CH=CH- underset(OH) underset(|)(CH)-CH=CH-CH_(3) is :

Total number of stereoisomer of given compound will be : CH_(3)-underset(Cl) underset(|)(CH)-underset(Br) underset(|)(CH)-underset(OH) underset(|)(CH)-CH_(3)

The number of meso form of the given compound is : CH_(3)-underset(OH) underset(|)(CH)-underset(OH) underset(|)(CH)-underset(OH) underset(|)(CH)-CH_(3)

Total number of stereoisomers of compound CH_(3)-CH=CH-underset(overset(|)(CI))(C)H-CH=CH-CH_(3) are :

The IUPAC name of given compound is CH_3-underset(CH_2CH_3)underset(|)(CH)-CHO

Write the IUPAC names of the following compounds. (i) CH_(3)-CH_(2)-underset(OH)underset(|)(CH)-CH_(2)-CH_(2)-underset(CH_(3))underset(|)(CH)-CH_(2)-CH_(3) (ii) CH-=C-CH=CH-CH=CH_(2)

Write the name of the given compound CH_(3)-CH_(2)-CH_(2)-underset(CH_(3))underset(|)underset(CH-CH_(3))underset(|)CH-CH_(2)-CH_(2)-overset(CH_(2))overset(|)CH-CH_(3)

The IUPAC name of the compound is CH_(3)-underset(CH_(3))underset(|)(CH)-CH_(2)-CH(OH)-CH_(2)