In the given reaction `C_6H_5-CH_2-Br+AgCNrarrX` (major product) [X] will be

Options

A. `C_6H_5-CH_2CN`
B. `C_6H_5-CH_2NC`
C. `C_6H_5CH_2CONH_2`
D. `C_6H_5CONH_2`

Answer

To solve the reaction \( C_6H_5-CH_2-Br + AgCN \rightarrow X \), we will follow these steps:

### Step 1: Identify the Reactants
The reactants in this reaction are:
- Benzyl bromide (\( C_6H_5-CH_2-Br \))
- Silver cyanide (\( AgCN \))

### Step 2: Understand the Reaction Mechanism
In this reaction, silver cyanide acts as a nucleophile. The bromine atom in benzyl bromide is a good leaving group. When silver cyanide is introduced, it will replace the bromine atom.

### Step 3: Nucleophilic Substitution
The nucleophilic substitution occurs as follows:
- The cyanide ion (\( CN^- \)) from \( AgCN \) attacks the carbon atom that is bonded to the bromine in benzyl bromide.
- As a result, the bromine atom leaves, and the cyanide group attaches to the benzyl carbon.

### Step 4: Forming the Product
The product formed from this reaction is benzyl cyanide (\( C_6H_5-CH_2-CN \)), but since the question specifies the major product, we need to consider the isocyanide formation as well.

### Step 5: Final Product
The major product of this reaction is isocyanide, which is represented as:
\[ C_6H_5-CH_2-NC \]
This is because the reaction with \( AgCN \) can lead to the formation of isocyanide due to the rearrangement of the cyanide group.

### Conclusion
Thus, the major product \( X \) is \( C_6H_5-CH_2-NC \).

### Answer
The major product \( X \) is \( C_6H_5-CH_2-NC \).

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