Which of the following 0.1 M complex compound solutions will have the minimum electrical conductivity ?

Options

A. `[Pt(NH_3)_3Cl_3]Cl`
B. `[Pt(NH_3)_4Cl_2]Cl_2`
C. `[Pt(NH_3)_5Cl]Cl_3`
D. Hexaammine platinum (iv) chloride

Answer

To determine which of the following 0.1 M complex compound solutions will have the minimum electrical conductivity, we need to analyze the dissociation of each complex compound into ions in solution. The conductivity of a solution is directly proportional to the number of ions present; therefore, the compound that produces the least number of ions upon dissociation will have the minimum electrical conductivity.

### Step-by-Step Solution:

1. **Identify the Complex Compounds**:
Let's denote the complex compounds as follows:
- Compound A: [Pt(NH3)5Cl]Cl2
- Compound B: [Pt(NH3)4Cl2]Cl
- Compound C: [Pt(NH3)6Cl]Cl4
- Compound D: [Pt(NH3)5Cl3]

2. **Dissociation of Each Compound**:
We will analyze how many ions each compound produces when dissolved in water.

- **Compound A: [Pt(NH3)5Cl]Cl2**
- Dissociates into: 1 [Pt(NH3)5Cl] + 2 Cl⁻
- Total ions = 1 (coordination ion) + 2 (Cl⁻) = **3 ions**

- **Compound B: [Pt(NH3)4Cl2]Cl**
- Dissociates into: 1 [Pt(NH3)4Cl2] + 1 Cl⁻
- Total ions = 1 (coordination ion) + 1 (Cl⁻) = **2 ions**

- **Compound C: [Pt(NH3)6Cl]Cl4**
- Dissociates into: 1 [Pt(NH3)6Cl] + 4 Cl⁻
- Total ions = 1 (coordination ion) + 4 (Cl⁻) = **5 ions**

- **Compound D: [Pt(NH3)5Cl3]**
- Dissociates into: 1 [Pt(NH3)5Cl3] + 3 Cl⁻
- Total ions = 1 (coordination ion) + 3 (Cl⁻) = **4 ions**

3. **Compare the Number of Ions**:
- Compound A: 3 ions
- Compound B: 2 ions
- Compound C: 5 ions
- Compound D: 4 ions

4. **Determine the Minimum Conductivity**:
Since conductivity is directly proportional to the number of ions, the compound that produces the least number of ions will have the minimum electrical conductivity.

- Compound B produces the least number of ions (2 ions).

### Conclusion:
The complex compound solution that will have the minimum electrical conductivity is **Compound B: [Pt(NH3)4Cl2]Cl**.