The IUPAC name of the compound, `CH_2=underset(CH_3)underset(|)C-CH_2-C-=CH` is

Options

A. 2- Methylpent -1-en-4-yne
B. 4- Methylpent -4-en-1-yne
C. 2- Methylpent -2-en-4-yne
D. 4- Methylpent -2-en-1-yne

Answer

To determine the IUPAC name of the compound `CH2=CH(CH3)C-CH2-C≡CH`, we will follow these steps:

### Step 1: Identify the Longest Carbon Chain
First, we need to identify the longest continuous carbon chain in the compound. In this case, the longest chain consists of 5 carbon atoms.

### Step 2: Number the Carbon Chain
Next, we will number the carbon chain. We need to give priority to the double bond over the triple bond when numbering.

- If we start from the left (where the double bond is), we have:
1. C1 (double bond)
2. C2 (methyl group attached)
3. C3
4. C4 (triple bond)
5. C5

- If we start from the right, the triple bond would get the lowest number, which is not preferred since the double bond has higher priority.

Thus, we number the chain from left to right.

### Step 3: Identify the Functional Groups
- The double bond is located between C1 and C2.
- The triple bond is located between C4 and C5.
- There is a methyl group (-CH3) attached to C2.

### Step 4: Construct the Name
Now we can construct the name based on the following:
- The base name for 5 carbon atoms is "pent".
- The double bond at C1 gives us "1-ene".
- The triple bond at C4 gives us "4-yne".
- The methyl group at C2 gives us "2-methyl".

Putting it all together, the IUPAC name of the compound is **2-methyl-1-pentene-4-yne**.

### Final Answer
**2-methyl-1-pentene-4-yne**