In the reaction `CH_3-CH_2-OHunderset((ii)LiAiH_4)overset((i)TsCl)rarr(X)` , (X) will be

Options

A. `CH_2=CH_2`
B. `CH_3-CH_2-CH_2-CH_3`
C. `CH_3-CH_3`
D. `CH_3-CH=CH-CH_3`

Answer

To solve the question, we will break down the reaction step by step.

### Step 1: Identify the Reactants
The reactant given is ethanol, which has the molecular formula \( CH_3-CH_2-OH \). Ethanol is a two-carbon alcohol.

### Step 2: Reaction with Tosyl Chloride
The first step in the reaction involves treating ethanol with tosyl chloride (\( TsCl \)). Tosyl chloride is a reagent used to convert alcohols into better leaving groups. The reaction can be represented as follows:

\[ CH_3-CH_2-OH + TsCl \rightarrow CH_3-CH_2-OTs + HCl \]

In this reaction, the hydroxyl group (\( -OH \)) of ethanol is converted into a tosylate (\( -OTs \)), which is a better leaving group. The product formed is ethyl tosylate (\( CH_3-CH_2-OTs \)).

### Step 3: Reduction with Lithium Aluminium Hydride
The next step involves the reduction of ethyl tosylate using lithium aluminium hydride (\( LiAlH_4 \)). Lithium aluminium hydride is a strong reducing agent that can reduce tosylates to alkanes. The reaction can be represented as follows:

\[ CH_3-CH_2-OTs + LiAlH_4 \rightarrow CH_3-CH_2-H + LiOTs + AlH_3 \]

In this step, the tosylate group (\( -OTs \)) is replaced by a hydrogen atom, resulting in the formation of ethane (\( CH_3-CH_2-H \)).

### Final Product
The final product \( X \) after these reactions is ethane (\( C_2H_6 \)), which can be represented as:

\[ X = CH_3-CH_2-H \]

### Conclusion
Thus, the product \( X \) in the reaction is ethane.