In the reaction sequence `CH_3-CH_2-COOHoverset(H_2O_2)rarr[X]overset(Delta)rarr[Y]` [Y] will be

Options

A. `CH_3-overset(OH)overset(|)(CH)-COOH`
B. `CH_2=CH-COOH`
C. `overset(OH" ")overset(|" ")(CH_2)-CH_2-COOH`
D. Lactide

Answer

To solve the problem, we need to analyze the reaction sequence given:

1. **Starting Compound**: The starting compound is propanoic acid, which can be represented as CH3-CH2-COOH.

2. **First Reaction with H2O2**: When propanoic acid (CH3-CH2-COOH) is treated with hydrogen peroxide (H2O2), it forms a peroxy acid. The reaction can be represented as:
\[ \text{CH}_3\text{-CH}_2\text{-COOH} + \text{H}_2\text{O}_2 \rightarrow \text{CH}_3\text{-CH}_2\text{-C(=O)O-OH} \quad \text{(Peroxy acid)} \]
This product is denoted as [X].

3. **Heating the Peroxy Acid**: The next step involves heating the peroxy acid [X]. During this heating process, a molecule of water (H2O) is eliminated. The reaction can be summarized as:
\[ \text{CH}_3\text{-CH}_2\text{-C(=O)O-OH} \overset{\Delta}{\rightarrow} \text{CH}_2=CH-COOH + \text{H}_2\text{O} \]
The product formed after the elimination of water is an unsaturated carboxylic acid, specifically, acrylic acid (CH2=CH-COOH).

4. **Final Product [Y]**: Therefore, the final product [Y] after the heating step is:
\[ \text{Y} = \text{CH}_2=CH-COOH \quad \text{(Acrylic acid)} \]

### Final Answer:
The product [Y] will be **CH2=CH-COOH (Acrylic acid)**.