0.73 g of orgainc compound on oxidation gave 1.32 g of carbon dioxide. The percentage of carbon in the given compound will be

Options

A. 49.32
B. 59.32
C. 29.32
D. 98.64

Answer

To find the percentage of carbon in the given organic compound, we will follow these steps:

### Step 1: Calculate the moles of CO2 produced
The formula to calculate moles is:
\[ \text{Moles} = \frac{\text{Mass}}{\text{Molar Mass}} \]
Given:
- Mass of CO2 = 1.32 g
- Molar mass of CO2 = 44 g/mol

Calculating the moles of CO2:
\[ \text{Moles of CO2} = \frac{1.32 \, \text{g}}{44 \, \text{g/mol}} = 0.03 \, \text{mol} \]

### Step 2: Determine the moles of carbon
From the moles of CO2, we can find the moles of carbon (C) since each molecule of CO2 contains one atom of carbon:
\[ \text{Moles of C} = \text{Moles of CO2} = 0.03 \, \text{mol} \]

### Step 3: Calculate the mass of carbon
To find the mass of carbon, we use the formula:
\[ \text{Mass} = \text{Moles} \times \text{Molar Mass} \]
Given the molar mass of carbon (C) is 12 g/mol:
\[ \text{Mass of C} = 0.03 \, \text{mol} \times 12 \, \text{g/mol} = 0.36 \, \text{g} \]

### Step 4: Calculate the percentage of carbon in the organic compound
The percentage of carbon in the organic compound can be calculated using the formula:
\[ \text{Percentage of C} = \left( \frac{\text{Mass of C}}{\text{Mass of organic compound}} \right) \times 100 \]
Given the mass of the organic compound is 0.73 g:
\[ \text{Percentage of C} = \left( \frac{0.36 \, \text{g}}{0.73 \, \text{g}} \right) \times 100 \approx 49.32\% \]

### Final Answer:
The percentage of carbon in the given organic compound is approximately **49.32%**.

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