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On adding excess of AgNO3 solution into ...

On adding excess of `AgNO_3` solution into 0.01mole complex compound `PtBr_4. xNH_3,0.03` moles yellow precipitate was obtained , the value of 'x' is

A

2

B

3

C

4

D

5

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the information given about the complex compound \( PtBr_4 \cdot xNH_3 \) and the reaction with \( AgNO_3 \). ### Step-by-Step Solution: 1. **Identify the reaction and the precipitate formed**: - When excess \( AgNO_3 \) is added to the complex compound, a yellow precipitate of \( AgBr \) is formed. This indicates that bromide ions are being released from the complex. 2. **Determine the moles of precipitate formed**: - The problem states that 0.03 moles of \( AgBr \) precipitate were formed. This means that 0.03 moles of bromide ions were released from the complex. 3. **Relate the moles of \( AgBr \) to the bromide ions in the complex**: - Since \( AgBr \) is formed from bromide ions, the formation of 0.03 moles of \( AgBr \) implies that there are 0.03 moles of bromide ions available. 4. **Analyze the composition of the complex**: - The complex is given as \( PtBr_4 \cdot xNH_3 \). This indicates that there are 4 bromide ions in total in the complex. - If 3 bromide ions are outside the coordination sphere (as indicated by the formation of 0.03 moles of \( AgBr \)), then only 1 bromide ion is left inside the coordination sphere. 5. **Determine the coordination number**: - The coordination number of the complex is typically 6 for platinum complexes. - Since we have 1 bromide ion inside the coordination sphere, we need to find out how many \( NH_3 \) ligands are required to reach a total coordination number of 6. 6. **Calculate the value of \( x \)**: - If there is 1 bromide ion inside the coordination sphere, we need \( 6 - 1 = 5 \) \( NH_3 \) ligands to complete the coordination number. - Therefore, \( x = 5 \). ### Final Answer: The value of \( x \) is 5. ---
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