Consider the following sequence of reaction:
`Na+NH_(3)(g) to [X]overset(N_(2)O)to[Y] overset(Heat)tounderset("Gas pure")([Z])`
Identify [Z] gas:

Options

A. `N_2`
B. `NH_3`
C. `O_2`
D. None of these

Answer

To solve the problem step by step, let's analyze the sequence of reactions provided:

1. **First Reaction: Sodium and Ammonia**
- The first reaction is between sodium (Na) and ammonia (NH₃) gas.
- When sodium reacts with ammonia, it forms sodium amide (NaNH₂).
- Therefore, we can denote this product as [X].
- **Reaction:**
\[ \text{Na} + \text{NH}_3 \rightarrow \text{NaNH}_2 \quad [X] \]

2. **Second Reaction: Sodium Amide and Nitrous Oxide**
- The next step involves the reaction of sodium amide (NaNH₂) with nitrous oxide (N₂O).
- This reaction leads to the formation of sodium azide (NaN₃).
- We can denote this product as [Y].
- **Reaction:**
\[ \text{NaNH}_2 + \text{N}_2\text{O} \rightarrow \text{NaN}_3 \quad [Y] \]

3. **Third Reaction: Heating Sodium Azide**
- The final step involves heating sodium azide (NaN₃).
- Upon heating, sodium azide decomposes to produce nitrogen gas (N₂) and sodium.
- This nitrogen gas is what we denote as [Z].
- **Reaction:**
\[ \text{NaN}_3 \xrightarrow{\text{Heat}} \text{N}_2 + \text{Na} \quad [Z] \]

4. **Conclusion: Identifying [Z]**
- From the above reactions, we can conclude that the gas produced, which is [Z], is nitrogen (N₂).

Thus, the final answer is:
\[ \text{[Z] gas is } \text{N}_2 \]